College Algebra Exercises Section 2.7
5) Find the inverse of the function f whose rule is f(x) = 6x.
Solution: The function f multiplies domain
elements by 6.
To "undo" this multiplication by 6, the inverse of f must be a function
which divides by 6.
Therefore the rule for the inverse f -1 will be
6) Find the inverse of the function f whose
rule is
.
Solution: The function f multiplies domain elements
by
.
To "undo" this multiplication by
,
the inverse of f must be a function which multiplies by 3..
Therefore the rule for the inverse f -1 will be f -1(x)
= 3x.
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10) Find the inverse of the function f whose
rule is
.
Solution: This function subtracts 1 from domain elements
and then divides that difference by 5.
To "undo" these two operations, the inverse of f must multiply by
5 and then add 1 to that product.
Therefore the rule for the inverse f -1 will be
.
13) Show that the functions f and g are inverses
of each other.
Their rules are: f(x) = 2x and
.
Solution:
![]()
Therefore the functions f and g are inverses of each other.
16) Show that the functions f and g are inverses
of each other.
Their rules are f(x) = 3 - 4x and ![]()
Solution:

Therefore the functions f and g are inverses of each other.
17) Show that the reciprocal function
whose rule is
is its own inverse.
Solution:
To verify that f is its own inverse we must show that ![]()
Therefore f is its own inverse.
24) Show that the functions f and g are
inverses of each other.
Solution:
Therefore the functions f and g are inverses of each other.