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MATH
140 -- Intermediate Algebra -- Exercise Solutions
Section: 2.3
2. Solve
W = gh for h
Solution:
Divide both sides of the equation by g
(
Note that when doing this we assume that g is not 0 and in fact the result will
be true only if g is not 0)
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4. Solve
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Solution:
Divide both sides of the equation by wh
(
Note that when doing this we assume that wh is not 0 and in fact the result
will be true only if wh is not 0)
6.
Solve 2x + 3y = 17 for y
Solution:
2x + 3y = 17
Add
- 2x to both sides of the equation
3y = -2x + 17
Divide
both sides of the equation by 3
8. Solve
A = 3M - 2N for N
Solution:
A = 3M - 2N
Add
- 3m to both sides of the equation
A - 3M = - 2N
Divide
both sides of the equation by -2
which may be rewritten as
10. Solve
y = mx + b for x
Solution:
y = mx + b
Subtract
b from both sides (Add - b to both sides)
y - b = mx
Divide
both sides of the equation by m
(
Note that when doing this we assume that m is not 0 and in fact the result will
be true only if m is not 0)
12. Solve
A = Prt + P for P
Solution:
A = Prt + P
Use
the Distributive Law to factor P from the sum on the right side of the equation
A = P(rt + 1)
Divide
both sides of the equation by rt + 1
( Note that
when doing this we assume that rt + 1is not 0 and in fact the result will be
true only if rt
+ 1
is not 0)
14. Solve
A = 5H(b + B) for B
Solution:
A = 5H(b + B)
Use
the Distributive Law to do the multiplication on the right side of the equation
A = 5Hb + 5HB
Subtract
5Hb from both sides of the equation
A - 5Hb = 5HB
Divide
both sides of the equation by 5H
(
Note that when doing this we assume that H is not 0 and in fact the result will
be true only if H is not 0)
16. ![]()
Solution:
Subtract
from both sides of the equation
Divide
both sides of the equation by ![]()
18. Solve
A = P(1 + rt) for t
Solution:
A = P(1 + rt)
Use
the Distributive Law to do the multiplication on the right side of the equation.
A = P + Prt
Subtract
P from both sides of the equation
A - P = Prt
Divide
both side of the equation by Pr