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MATH
140 -- Intermediate Algebra -- Exercise Solutions
Section: 3.6
26.
Graph x - 4y < 8
Answer: The equation of the boundary
line is x - 4y = 8. Its graph is

Use (0, 0) as a test point.
When the coordinates of (0, 0) are substitued into the inequality we obtain
0 - 4(0) < 8 a TRUE statement.
Therefore the solution set for x - 4y < 8 is the half-plane containing
(0, 0). Because this is a strict inequality the boundary line is not part
of the solution and is drawn as a dashed line.
The graph of x
- 4y < 8
is:
28.
Graph y ≥ - 2
Answer:
The equation of the boundary line is
y = - 2. Its graph is
Use (0, 0) as a test point.
When the coordinates of (0, 0) are substitued into the inequality we obtain
0 ≥ -2 a TRUE statement.
Therefore the solution set for y ≥ - 2 is the half-plane containing (0,
0). Because this inequality permits equality the boundary line is part of
the solution and is drawn as a solid line.
The graph of y
≥ - 2
is:
30.
Graph - 3x + y ≤ 9
Answer:
The equation of the boundary line is
- 3x + y = 9. Its graph is

Use (0, 0) as a test point.
When the coordinates of (0, 0) are substitued into the inequality we obtain
-3(0) + 0 ≤ 9 a TRUE statement.
Therefore the solution set for -3x + y ≤ 9 is the half-plane containing
(0, 0). Because this inequality permits equality the boundary line is part
of the solution and is drawn as a solid line.
The graph of -
3x + y ≤ 9
is:
32.
Graph x + 2y > 0
Answer:
The equation of the boundary line is
x + 2y = 0. Its graph is
Use
(1, 1) as a test point. When
the coordinates of (1, 1) are substitued into the inequality we obtain
1 + 2(1) > 0 a TRUE statement.
Therefore the solution set for x + 2y > 0 is the half-plane containing
(1, 1). Because this is a strict inequality the boundary line is not part
of the solution and is drawn as a dashed line.
The graph of x
+ 2y > 0 is:
34.
Graph 2x - 3y ≤ 9
Answer:
The equation of the boundary line is
2x
- 3y =
9. Its graph is
Use (0, 0) as a test point.
When the coordinates of (0, 0) are substitued into the inequality we obtain
2(0) - 3(0) ≤ 9 a TRUE statement.
Therefore the solution set for 2x - 3y ≤ 9 is the half-plane containing
(0, 0). Because this inequality permits equality the boundary line is part
of the solution and is drawn as a solid line.
The graph of 2x - 3y ≤ 9
is:
36.
Graph the union of x - y < 3 and
x > 4
Answer:
The equation of the boundary line of
x - y < 3 is x - y = 3 and the
boundary line of x > 4 is x
= 4 Their graphs are

Use
(0, 0) as a test point.
for both inequalities.
When the coordinates of (0, 0) are substituted into the blue inequality a
true statement is obtained. Therefore the solution set for the blue inequality
is the half-plane containing (0, 0). Because
this is a strict inequality the boundary line is not part of the solution
and is drawn as a dashed line.
When the coordinates of (0, 0) are substituted
into the red inequality a false statement is obtained. Therefore the solution
set for the red inequality is the half-plane which does not contain (0, 0).
Because this is a strict inequality the boundary line is not part of the solution
and is drawn as a dashed line. The individual graphs of the two inequalities
are

The
union is both sets--the points shaded in blue as well as the points shaded
in red. This is properly stated as the blue points OR the
red points. Note the inclusive nature of how the word OR
is used in mathematics.The graph of the union is obtained by combining the
two graphs. The graph of the union is
38.
Graph the intersection of y≥x and
2x - 4y ≥ 6
Answer:
The equation of the boundary line of
y≥x
is x = y and the boundary
line of 2x
- 4y ≥ 6
is 2x
- 4y
= 6 Their graphs are

Use (2, 1) as a test point for the blue inequality to obtain 1 ≥ 2 a FALSE
statement. Therefore the half-plane which does not contain the point (2, 1)
is the solution to the blue inequality. Because
this inequality permits equality the boundary line is part of the solution
and is drawn as a solid line.
Use (0,0) as a test point for the red inequality to obtain 2(0) - 4(0) ≥
6 which is a FALSE statement. Therefore the half-plane which does not contain
the point (0, 0) is the solution to the red inequality. Because
this inequality permits equality the boundary line is part of the solution
and is drawn as a solid line. The
individual graphs of the two inequalities are
The intersection is the set of point common to both sets--the points shaded
in blue AND shaded in red. The graph of the intersection
is obtained by combining the two graphs. The graph of the intersection is
the region in the following graph which is shaded bot red and blue.